Antenna azimuth controller design

The problem presented to our

team was to analyze and

implement a controller on a off

the shelf antenna azimuth

position control system.

We analyzed the open loop and

closed loop characteristics of the

system and determined the most

stable and implementable

controller for the system.

Our suggested solution to the

presented problem is to

implement a PID controller

ahead of the Power Amplifier but

after the Preamplifie

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HCM CITY UNIVERSITY OF TECHNOLOGY 
----------
TOPIC:ANTENNA AZIMUTH CONTROLLER DESIGN
GROUP 11: 
BÙI GIA BẢO 41100210 
DƯƠNG MINH THÀNH 41103193 
Ễ Ầ ÂNGUY N TR N XU N SƠN 41102943 
NGUYỄN PHI QUỐC THANH 41103138
SUMMARY:
The problem presented to our 
team was to analyze and 
implement a controller on a off 
the shelf antenna azimuth 
position control system.
We analyzed the open loop and 
closed loop characteristics of the 
system and determined the most 
stable and implementable 
controller for the system.
Our suggested solution to the 
presented problem is to 
implement a PID controller 
ahead of the Power Amplifier but 
after the Preamplifier. 
A.Overview block diagram
B Subsystem.
C.Design the controller
Refrerences: 
-people.clarkson.edu/~estradjm/Satellite_Tracking
-Project Engineer: Liu Xuan
-docstoc com/docs/137820424/AZIMUTH-ANTENNA-.
CONTROL-SYSTEM-DESIGN
A.Overview block diagram
BLOCK DIAGRAM
SCHEMATIC
B.Subsystem
1.SUBSYSTEM 1:Kpot
The potentiometer changes the input angle, 
Фm(s) to a voltage, Vi(s). 
2. SUBSYSTEM 2: Preamplifier K
The purpose of the preamplifier is to take 
the input signal voltage and output a 
voltage that the power amplifier can use. 
3.SUBSYSTEM 3: Power amplifier
This requires the Power Amplifier to 
output a significant amount of power, 
thi th t th P lifi i tsome ng a e reamp er s no 
capable of. 
4.SUBSYSTEM :MOTOR AND LOAD
1.TRANSFER FUNCTION FOR CLOSED-LOOP SYSTEM:
C.Design the controller
When k=1
When k=44
When k=10
When k=5
When k=2.25
POT< 5%; t <3s; e 0(step input)
2.DESIGN DISCRETE LEAD COMPENSTATOR USING RL
 ss ss= ξ= 0.8; ωn=1.5 rad/s so r=0.88692; 
φ=0.09
Z1.2*= 0.88333 ± j0.07972Ф* = 48.66º
COMPARISON
Not meet theSimple, easy to 
implement
high 
requirements
P controller
Meet the highLead phase 
requirements More complex
controller

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